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`(3)/(2)`2`(2)/(3)`3

Answer :

BSolution :

Differentiating both sides <br> `x^(3) + 3 (ky)^(3) = k^(3)`, `3x^(2) + 9k^(3) y^(2) (dy)/(dx) = 0` <br> `(dy)/(dx) = - (x^(2))/(3k^(3) y^(2))` <br> On comparing with given equation `- (1)/(3k^(3)) = - (1)/(24)`, `k^(3) = 8 implies k = 2`Transcript

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00:00 - 00:59 | hello students in this question we have given equation x cube + 3 k y whole cube equal to K cube and also given relation that DY by DX + x square divided by 24 y square equal to zero and we need to find the value of k so basically we have given that x cube + 3 k y whole cube equal to K Q from here we can write as this is equal to x cube + 3 x cube b cube equal to kq now we have to differentiate bowsette CBSE grade differentiate both sides both sides we can get basically d by DX of X raise to power n equal to n x power n -1 from here we can write this is equal to 3 X square + 3 x cube x 3 |

01:00 - 01:59 | square DY by DX equal to zero so from here we can write as DY by DX DY by DX equal to disturb goes to tighten side so we can write is minus 3 x square / and this whole town this whole town ghost am so we can write s3k cube x 3 y square so from here we can write has minus x square divided by 3 cube square from here we can write as DY by DX DY by DX + x square divided by 3 ke cube y square is equal to zero basically we have to transfer this whole turn into left hand side and in the question it is given that DY by DX + |

02:00 - 02:59 | x square y square so we can write as DY by DX + x square divided by 24 y square is equal to zero by comparing these two equation these two equation we have to compare so we can get 3K Q3 ke Q Basic system and this term is equal 24 from here we can write as ke cube equal to 24 B three which equal to 8 kq equal to 8 so we can write s k = 22 this is the value of k from option we can say that option number 2 is correct thank you |

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